What is the value of x? Round your answer to the nearest tenth if necessary.

http://static.k12.com/calms_media/media/1577500_1578000/1577938/1/c840947ced6d410d5858579e26880ce72f28d4db/MS_IMC-150120-130106.jpg

Question

What is the value of x? Round your answer to the nearest tenth if necessary. 

http://static.k12.com/calms_media/media/1577500_1578000/1577938/1/c840947ced6d410d5858579e26880ce72f28d4db/MS_IMC-150120-130106.jpg

ondinana · Answer

@user3

anonymous · Answer

Okay, on this one we know a and c, and have to solve for b

ondinana · Answer

So how does that change it from the last question?

anonymous · Answer

We have now $6^2 + b^2 = 17^12$

anonymous · Answer

*$17^2$

ondinana · Answer

So, couldn't I just subtract the two somehow for my answer?

ondinana · Answer

Or what do I do lol

ondinana · Answer

@user3 ?

anonymous · Answer

We need to square the given values

ondinana · Answer

Okay, then that would be 36+b^2= 289 right?

anonymous · Answer

Yes, now we can subtract 36 from both sides

ondinana · Answer

Ok so then it would be.. ____+b^2=253?

anonymous · Answer

Yes, so just $b^2 = 253$, then take the square root and we have b :)

ondinana · Answer

15.9??? :D

ondinana · Answer

That's the answer right? Or did I do something different lol. @user3

anonymous · Answer

Yep, that is correct :)

ondinana · Answer

Yeee, thanks again! ^_^ I got a 100! :D

anonymous · Answer

No problem :) I hope this wasn't a test...

ondinana · Answer

Naw, it's just like a quiz after each lesson to see if I understood the lesson. I was just stumped on the last 2. XD

anonymous · Answer

ah ok :) I understand the pains of end of lesson reviews

ondinana · Answer

Indeed. :P