Question

Find the general solution.

Answer 1

\[sinx+\sqrt{2}=-sinx\]

Answer 2

I got sinx=-sqrt2/2

Answer 3

3rd and 4th quadrants?

Answer 4

225 degrees+2npi
315 degrees+2npi

?

Answer 5

@mathmath333

Answer 6

\[\sin(x)+\sqrt{2}=-\sin(x)\]\[\sqrt{2}=-2\sin(x)\]\[-\sqrt{2}/2=\sin(x)\]

Answer 7

Yes..

Answer 8

lol

Answer 9

so, your solution is pretty much that, but in a different quadrant.... good luck !

Answer 10

5pi/3+2npi

and converting 315 degrees rn..

Answer 11

7pi/4+2npi

Answer 12

correct?

Answer 13

I am getting
\[2 \pi n-\frac{\pi}{4}\]\[2 \pi n+\frac{5\pi}{4}\]

Answer 14

Oh yeah, I converted 225 degrees incorrectly

Answer 15

but what about 7pi/4+2npi?

Answer 16

i mean considering if i couldn't use -45 degrees as an answer

Answer 17

all these pi's.... I will check wolfram real quick.

Answer 18

alright thanks

Answer 19

http://www.wolframalpha.com/input/?i=sin%28x%29%2Bsqrt%282%29%3D-sin%28x%29

Answer 20

he is talking 1/4 th out

Answer 21

https://www.symbolab.com/solver/trigonometric-identity-calculator/sin%5Cleft(x%5Cright)%2B%5Csqrt%7B2%7D%3D-sin%5Cleft(x%5Cright)/?origin=button

Answer 22

i think im right