What is the limit of e^x as x approaches negative infinity?
\(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~-\infty}~e^x}\)
you can tell just by logical analysis.
oh, duh.... zero?
yes, \(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~-\infty}~e^{x}=0}\)
lol... well i'm working with \[\lim_{x \rightarrow -\infty}\frac{ e^x+e ^{-x} }{e^x-e ^{-x} ? }\]
oh, that is a bit different, or at least looks different.
what I thought was that I'm suppose to divide each term by \[e^x\] but, i'm doubting myself
yes, I don't think it would work, because then you get (roughly)\[\frac{0 +( \infty )}{0-(\infty)}\]
which would make the answer negative infinity?
well, actually, it can work....
let me think
yes, it works
then you get -1
and wouldn't it be \[\frac{ 1+\infty }{1-\infty }\]?
well, the limit of e^x as x approaches - infty is 0. isn't it so ?
oh oh, got it
so, if you separate the whole limit into a bunch of limits, you get (- infty) / (+ infty) which would be -1
and these infinities here are in/de creasing with the exact same maginute
magnitude*
I might be here a bunch, I got really behind due to a brutal winter that my immune system does not like, thanks Solomon
the school and work systems don't like it either .... a couple of snowflakes fell (which they called a "snowstorm") and the city was paralyzed.
... have a warm weather :)
lol, you won't find that in Cleveland.... not for a while.... thanks again! peace
|dw:1427151818643:dw|
would be easier to use `\(\large\color{blue}{ \heartsuit }\)` which gives: \(\large\color{blue}{ \heartsuit }\) . you can change the color "blue" to "black", "green", "magenta" or any other.
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