Question

Finding distance in a Triangle

Answer 1

http://puu.sh/gNkPo/3cafb56412.jpg this is the question, I'm not sure how to start.

Answer 2

hmmm not sure myself..
at first looks like a geometric sequence
but we don't have any values to use

Answer 3

Yeah, I'm not sure... I just know that the answer should contain "b"

Answer 4

good one -
1st section = b
2nd section = b*sin(56)
3rd section = b*sin(56)*sin(56) = b*(sin(56))^2 u can find this by looking at the new smaller triangle formed
4th section = b*(sin(56))^3
...
nth section = b*(sin(56)^(n-1)

You will get there when n approaches infinity so the total distance traveled = 1st section + 2nd section + ... + nth section + ....

It is a geometric series and you can find the answer from b*(1-R^n)/(1-R) where R is the common ratio and n is infinity.

Good luck!