Question

Simple Integral Question!

Answer 1

\[\int\limits_{}^{} 4 \sqrt{y+1} dy\]

Answer 2

\[4* 2/3 (y+1)^(3/2) dy * y^2/ 2?\]

Answer 3

u = y + 1

Answer 4

Okay I know how to solve this but why do we not integrate the y+1 part?

Answer 5

what do you mean

Answer 6

Sorta like chain rule? Why do not not integrate the expression in the parentheses?

Answer 7

do you see what I am saying? :) @perl

Answer 8

yes i do

Answer 9

Just take out your constant first. \[4\int\sqrt{y+1}dy\]\[u=y+1~,~ du =dy\]

Answer 10

\[\Large y+1 = u^2 \\ \Large dy=2udu\] Plug this in: \[\Large \int\limits 8u^2du= \frac{8}{3}u^3+C\] don't forget to resubstitute back in \[\Large \frac{8}{3} (1+y)^{3/2}+C\]

Answer 11

Always one step ahead.

Huge font = huge ego. =^_____^=

Answer 12

No, I have bad vision from staying up late too many nights doing math so I make the font large so I can read it lol