Taking a voltage-current graph for an Ohmic resistor, why is it necessary to take values of change in V and divide it by change in I for finding the Resistance of the Resistor. Why don't we just divide any given value of V with the corresponding value of I?

Question

anonymous · Answer

You should be able to do that and get the same result with an ohmic resistor. I don't know of any reason why you can't just divide a given value of V by its corresponding value of I.

radar · Answer

Note, that the problem is the development of a "graph" or a  load line presented by a resistor, to obtain at least 2 points you would use multivalues of voltage with the resultant current.  You should get a linear graph (a line) whose slope is equal to the value of the resistor.

anonymous · Answer

Good. I didn't interpret the question like that.

radar · Answer

It was the impression that I got, but as you have indicated, dividing its given value by E will locate a point that will exist on that line.