Question

Normal approximation for Binomial Distribution. I am using the correct formula, but my answer is wrong. I think it may be due to round off. Attached image.

Answer 1

\[P(X>= 208) = \frac{ 208 - 1000*0.193 }{ \sqrt{1000*0.193*0.807} } \rightarrow z=1.2019 \]

Answer 2

z of 1.2019 = 0.8853 (approx)\[P(x \ge208) = 1-0.8853 = 11.47\]

Answer 3

There was a similar problem and my answer was really close.

Answer 4

It looks correct

Answer 5

The answer is 0.1071. I hate these lol. Thanks for confirming.