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Mathematics 10 Online
OpenStudy (howard-wolowitz):

ONE QUESTION

OpenStudy (michele_laino):

here, I think to conjecture a linear relationship between x= number of months, and y = number of sunscription, namely: y=ax+b

OpenStudy (michele_laino):

so we have to solve the subsequent system: \[\left\{ \begin{gathered} 5730 = 5a + b \hfill \\ 6022 = 7a + b \hfill \\ \end{gathered} \right.\]

OpenStudy (michele_laino):

where a and b have to be determined, using, for example the substitution method

OpenStudy (michele_laino):

hint: I solve the first equation, and I get: b= 5730-5a

OpenStudy (michele_laino):

next I substitute that value for b inthe secon equation, as below: \[6022 = 7a + 5730 - 5a\]

OpenStudy (michele_laino):

what is a?

OpenStudy (howard-wolowitz):

one sec im doing it

OpenStudy (howard-wolowitz):

146

OpenStudy (michele_laino):

ok!

OpenStudy (michele_laino):

now I substitutte that value for a into the first equation, for example, and I get: \[b = 5730 - 5a = 5730 - 5 \times 146 = ...?\]

OpenStudy (michele_laino):

then what is b?

OpenStudy (howard-wolowitz):

5730-5a

OpenStudy (michele_laino):

yes, and a = 146, so: b = 5730 - 5* 146= 5730 - 730= ...?

OpenStudy (howard-wolowitz):

5000?

OpenStudy (michele_laino):

perfect!

OpenStudy (michele_laino):

so our relationship, is: \[y = 146x + 5000\]

OpenStudy (howard-wolowitz):

sorry i confused myself but i understand now

OpenStudy (michele_laino):

ok!

OpenStudy (howard-wolowitz):

solve that ^

OpenStudy (michele_laino):

now, we have to set x= 10 into the previous formula, and then we have to compute y: \[y = 146x + 5000 = 146 \times 10 + 5000 = ...?\]

OpenStudy (michele_laino):

what is y?

OpenStudy (michele_laino):

hint: \[146 \times 10 + 5000 = 1460 + 5000 = ...?\]

OpenStudy (howard-wolowitz):

im not sure dude

OpenStudy (michele_laino):

why?

OpenStudy (howard-wolowitz):

do i just solve that straight out

OpenStudy (howard-wolowitz):

where do i start?

OpenStudy (michele_laino):

in order to answer to your problem, we have to write the right function which models your exercise. Now, I think you are studying the linear relationships, so I have conjectured a linear relationship between the months x and the subscription y. Then your starting point is this function: y= ax+b

OpenStudy (michele_laino):

Now, using your data, we have to determine the values of a and b. We got: a = 146, and b = 5000

OpenStudy (michele_laino):

finally we have to write how many are the Subscriptions after 10 months. In order to that we have to set x=10 into our formula, namely: y = 146*10 +5000 what do you get is the right answer to your problem

OpenStudy (howard-wolowitz):

yes but what i dont get is what do i solve for here ->b = 5730 - 5* 146= 5730 - 730=

OpenStudy (michele_laino):

there you are finding the value of the coefficient b: b= 5730-730=5000

OpenStudy (michele_laino):

so the function which models your problem is: y = 146x+5000

OpenStudy (howard-wolowitz):

so for x or y?

OpenStudy (howard-wolowitz):

i got 146

OpenStudy (michele_laino):

that's the value of a, furthermore, you have to evaluate y when x=10

OpenStudy (howard-wolowitz):

dang this one is Hard

OpenStudy (howard-wolowitz):

oh i se one sec

OpenStudy (howard-wolowitz):

6460

OpenStudy (howard-wolowitz):

SO D :)

OpenStudy (michele_laino):

congrats! you got the right answer

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