Question

Medals will be given

Here is the image of what needs to be done, use the notepad that is in the options......

Answer 1

@jigglypuff314 Help

Answer 2

@Michele_Laino Help please

Answer 3

Hello???

Answer 4

here we can write this formula:
\[x + y = 23\]
so the area A is:
\[A = xy = x(23 - x)\]
I supposed that your paved arrea is a rectangle.
Now A is a function of x

Answer 5

oops..area*

Answer 6

:O
I have no idea how that is supposed to work

Answer 7

next we can compute the first derivative of A, in order to get the requested dimension x, namely:
\[A' = 23 - 2x = 0\]
please solve for x, what do you get?
Keep in mind that x has to be a whole number

Answer 8

this is a 5th grade question and I'm helping my sister but i don't know how to help

Answer 9

please wait....

Answer 10

the function A is a parabola, so we have to compute the x-coordinate of its vertex

Answer 11

hehe I was thinking along the same lines of @Michele_Laino xD
#calculus
ok so if it is 5th grade level
I would think to make a table with the addends of half of 46
(so addends of 23)
(aka the pairs of numbers that add up to 23)

ex: 1+22
2+21
3+20
4+19
etc

and multiply the two numbers in the table and see which has the biggest area
1+22 -> 1*22 = 22 area
2+21 -> 2*21 = 42 area
2+20 -> 3*20 = 60 area
so on and so forth

Answer 12

\[A = xy = x(23 - x) = 23x - {x^2}\]

Answer 13

uh this is confusing

Answer 14

@Michele_Laino I think kids learn parabolas in 7th grade, not 5th
so the best option here is to simply make a table

Answer 15

ok! thanks! @jigglypuff314

Answer 16

im in 8th grade math 7th grade everything else but this is confusing

Answer 17

for example if we follow the table of @jigglypuff314 , we find that when x=12, and y=23-12=11, the area A is:
A = 12*11= 132
whereas when x= 13 and y=23-13=10, then area is
A = 130,
so we find that the maximum value of A is given for
x= 12 and y=11
or x= 11 and y=12

Answer 18

never mind ill just ask my stepmom

Answer 19

ok!

Answer 20

OK I have some time to type up a full answer >:)

Perimeter of a Rectangle = 2*(Length + Width)
They gave you the Perimeter as 46
so (Length + Width) = 46 / 2 = 23

knowing that the numbers we can use can only be integers, the biggest the Length or Width can be would be 22

so let's make a table like that!
Length | Width | Area [Length x Width]
------------------------------------
1 22 22
2 21 42
3 20 60
4 19 76
5 18 90
6 17 102
7 16 112
8 15 120
9 14 126
10 13 130
11 12 132
12 11 132
13 10 130
14 9 126
15 8 120
16 7 112
17 6 102
18 5 90
19 4 76
20 3 60
21 2 42
22 1 22

so what is the biggest Area that you see?
132
right?
so the combination of 11 by 12 (length by width) would give you the biggest area!