Can someone help me with graphing the function x^2-12x+64?

Question

anonymous · Answer

first factor the equation

anonymous · Answer

(x-16)(x+4)?

welshfella · Answer

yes thats right

welshfella · Answer

so now you can work out the zeros of the function ( where the graph cuts the x axis)

anonymous · Answer

16 and -4?

welshfella · Answer

you can also find the vertex by writing the function in vertex form
(x -a)^2 + b

anonymous · Answer

are you sure that's the right equation

welshfella · Answer

right 16 and -4 are the zeroes

anonymous · Answer

because you factored x^2-12x-64

anonymous · Answer

yes it's a weird assignment where i had to plug in my birthday for the equation so my original equation was (x-6)^2+28 and then i factored it out to get that

welshfella · Answer

oops  -  you are right @10115658

welshfella · Answer

the equation does n't factor

anonymous · Answer

ya that's what i got welshfella

anonymous · Answer

is there a way to graph that?

anonymous · Answer

are you sure its not minus 64?

welshfella · Answer

yes you can graph that  - there won't be any real roots though . The graph would not pass through the x-axis

anonymous · Answer

would it be better if it was minus 64? I think i can do that too.

welshfella · Answer

it its -64 then it will have the roots you said

welshfella · Answer

in vertex form  its (x -6)^2 + 28

so there will be a minimum value at the point (6,28)
the graph will be a parabola

welshfella · Answer

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