Question

help would be much appreciated

Answer 1

HI!!

Answer 2

we know that the y squared part comes first, but all your answers have that
since the foci are at \((0,4)\) and \((0,-4)\) we know the number under the y is \(4^2=16\)

Answer 3

scuze me not the foci, the vertices

Answer 4

that leave B and C
the asymptotes are \(\frac{b}{a}=\frac{4}{a}=\frac{1}{3}\) solve
\[\frac{4}{a}=\frac{1}{3}\] for \(a\)

Answer 5

you got that?

Answer 6

b?

Answer 7

hmmm
\[\frac{4}{a}=\frac{1}{3}\\
a=12\]

Answer 8

and \(12^2=144\) goes under the x term

Answer 9

OH ok. got it! gracias

Answer 10

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