Question

What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12?

Answer 1

what are the answer choices?

Answer 2

(–∞, –3]

[–3, ∞)

(–∞, 15]

[15, ∞)

Answer 3

solve for x :
\[-3 (6-2x) \ge 4x + 12\]
\[ -18 + 6x \ge 4x + 12\]
\[2x \ge 30\]
\[ x\ge 15\]
So the answer is D ) 15 to +infinity

Answer 4

do u have any idea?

Answer 5

yep D

Answer 6

@Ogziii is right

Answer 7

it would be d