Question

area of a triangle?

Answer 1

since the triangles are congreunt their areas are also same.
\[A=Base*Height/2\]
this is area of triangle

Answer 2

okay. i know that. but with the base being an equation im not entirely sure how ti solve this what is x in the base? lol how do i figure that out.

Answer 3

@ksanka ?

Answer 4

would it become 5x ?

Answer 5

fristi'm mistaken.
Area of firtst triangle is 9*(6x-5)/2, and the area of second is EF*(3x+1)/2.
Also we can use the Pythagorian theorem: ED^2=AC^2=9^2+(6x-5)^2
81+36x^2-60x+25=AC^2
36x^2-60+106=AC^2
that's how i think it has to start

Answer 6

okay can you walk me through the rest of it? it makes sense up to that point

Answer 7

i think the area isn't the number.ithink it has to be written with x.
I am kind of being confused the same as you are
@sleepyjess

Answer 8

@SolomonZelman
@TheSmartOne
@iambatman

Answer 9

yeah, because because there is x in the base i'm not sure how to attempt this.

Answer 10

@dtan5457
@Nnesha
@confluxepic

Answer 11

@Owlcoffee

Answer 12

base times hight divided by two.

Answer 13

i understand that emielei but as i said above, i'm not sure how to do this as there is x in the base.

Answer 14

We know that the triangles are congruent by Angle-Angle-Side, so BC = DF

Answer 15

i know that. so how should i go about solving the base then so that it's a whole number. that way i can solve the problem.

Answer 16

set the bases equal to each other if they're in congruent measurements

Answer 17

Set the equations for the sides equal to each other

Answer 18

by simplifying each?

Answer 19

6x - 5 = 3x + 1

Answer 20

x = 2 ?

Answer 21

Then solve for x

Answer 22

and if x = 2 then it would be A = (2*9)/2 ?

Answer 23

base * height /2
the base isn't 2