Question

can someone help

Answer 1

@mathmath333

Answer 2

15,4?

Answer 3

\(\large \color{black}{\begin{align}
&x+y=5------------(a)\hspace{.33em}\\~\\
&x-2y=2------------(b)\hspace{.33em}\\~\\~\\~\\
&\implies 2x+2y=10-------(a)(\normalsize \text{multiplying equation by 2})\hspace{.33em}\\~\\
&x-2y=2------------(b)\hspace{.33em}\\~\\~\\~\\

\end{align}}\)

Answer 4

add equation a and b now

Answer 5

do i add 5+10 and 2+2 ?

Answer 6

\(\large \color{black}{\begin{align}
&\implies 2x+2y=10-------(a)\hspace{.33em}\\~\\
&x-2y=2------------(b)\hspace{.33em}\\~\\
&\text{(a)+(b)}\hspace{.33em}\\~\\
&\implies (2x+2y)+(x-2y)=10+2\hspace{.33em}\\~\\

\end{align}}\)

now simplify

Answer 7

im confused do i have to find out what=10

Answer 8

u have to find out the values of \(x\) and \(y\)

Answer 9

do u know how to solve this

\(\implies (2x+2y)+(x-2y)=10+2\hspace{.33em}\\~\\\)

Answer 10

i dont thats y im on here i dont understand

Answer 11

k thank u im just giving up now

Answer 12

this is stuff i have to do from last semester and its hard i didnt do it because i didnt know how

Answer 13

\(\implies (2x+2y)+(x-2y)=10+2\hspace{.33em}\\~\\
\implies (2x+x)+(2y-2y)=12\hspace{.33em}\\~\\
\implies x(2+1)+2(y-y)=12\hspace{.33em}\\~\\
\implies x(3)+2(0)=12\hspace{.33em}\\~\\
3x=12\hspace{.33em}\\~\\
x=\dfrac{12}{3}=4\hspace{.33em}\\~\\
\)

see if that makes sense

Answer 14

kinda but theres 2 boxes to put numbers and it doesnt make sense so x=4 y =0 or 1

Answer 15

my answer were already 2,4 so 4 is right what is y?

Answer 16

put \(x=4\) in this original equation and find value of \(y\)

\(x+y=5 \)

Answer 17

1

Answer 18

yes

Answer 19

so its 4,1

Answer 20

yes

Answer 21

thanks alot