Question

Please Help Me

Answer 1

first n last are right but the second one is not

Answer 2

So the first one on 11?

Answer 3

\[\sin2x=2sinxcosx\]
substitute this in
re arrange to get the equation equal to 0
then take out a factor
and that is your answer

Answer 4

yep
try it @ohohaye

Answer 5

Oh, ok

Answer 6

Thank you, I think I got it

Answer 7

Only the second one is wrong, The solution is as follows
5sin(2x)=3cosx
=> 5*2*sinx*cosx=3cosx
=>10*sinx*cosx -3cosx=0
=>cosx(10sinx-3)=0

Answer 8

Oh, ok