Help Please!!! Begging you? I do not understand this and I really need help. Will fan and medal anybody who helps me (Algebra)
@TheSmartOne
Task 1 Part 1. Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses. f x x a b g x c x d Part 2. Show your work to prove that the inverse of f(x) is g(x). Part 3. Show your work to evaluate g(f(x)). Part 4. Graph your two functions on a coordinate plane. Include a table of values for each function. Include 5 values for each function. Graph the line y = x on the same graph.
Part 1\[f(x) = x+a/b\] (to clarify all those numbers) \[g(x)=cx-d\]
@Nnesha
what is f(g)?
f(x) = x + a/b f(g) is just f composed of g, instead of composed of x f(g) = g + a/b but we have a definition for g, use it f(g) = (cx-d) + a/b now the thing is, what defines an inverse?
@amistre64 may we go part by part please?
i thought we did :) lets start with what defines an inverse .... what can you tell me?
like f(g(x))=g(f(x))?
yeah, but somehtings missing f(g(x)) = g(f(x)) = x ^^
so lets set it up what is f(g)? this is what i worked up to start with cn work up g(f)? or ask me question if you get lost
ok i understand that is the inverse
So for part 1 i can put in any numbers right?
@amistre64
no, we are working it out to determine what numbers we can use. f(g) = cx-d + a/b what is g(f)?
g(f)=b/a+z-cx?
g(f) = c(f) - d ; replace f with its definition g(f) = c(x + a/b) - d g(f) = cx + ca/b - d not sure where z is coming from
ok thank you srry did not mean to put z (meant to pout d)
now since they have to equal x .... they have to equal each other at best f(g) = g(f) cx - d + a/b = cx + ca/b - d since both side have a -d, it cancels out and can be anything it wants to be; whats your favorite d value?
idk 2?
2 is fine; let d=2 cx + a/b = cx + ca/b now can you tell me, what c value we can use to make this true? give me an educated guess.
4?
4 might not be good notice that if c=1 1(x) + a/b = 1(x) + 1(a/b)
ok so d=4 c=1
well, you said d=2 so lets not go chagning things ... d=4 is fine but it helps to stay consistent
now a and b can be anything you like, what makes your favorite fraction?
so d=2 c =1 fine a = 3 b= 4
that should work like a charm
ok so lets fit it in may you do it please my mother is calling me
f(x) =3(1)-5 g(x)=1 +5/3
@amistre64 so part 1 is done
f(x) = x + a/b g(x) = cx - d fill in the values f(x) = x + (3)/(4) g(x) = (1)x - (2) now i have to see what we did wrong ..... since this didnt work out that well
ok thank you and we did nothing wrong :)
thats it tho, we cant do part 2 if part 1 isnt valid. f(g) = cx - d + a/b g(f) = c(x+a/b) - d cx - d + a/b = c(x+a/b) - d when c=1 x - d + a/b = x+a/b - d this should be true for all abd values but: f(x) = x + 3/4 and g(x) = x - 2 are not inverses so we would need to reevaluate the issue let a/b = d ... or if b=1, then a=d
let a = d = 2, ;et c = b = 1
wait can you just show me the new equation please?
for part 1, because you are typing bad and it does not make sense
if working with me is incompatible, then you might what to find/wait for someone else. feel free to repost the question if you want so that others would be better attracted to it.
srry i did not mean to say in that kind of way i meant to say repost i also type bad i just kind of yeah.... @amistre64 please help me so let's con.?
@amistre64
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