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Mathematics 18 Online
OpenStudy (anonymous):

Help! Thanks!

OpenStudy (anonymous):

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

this seems to ahve worked

OpenStudy (anonymous):

I guess. soooo... could you help out?

OpenStudy (amistre64):

using the scatter plot tool .. where is your tool?

OpenStudy (anonymous):

I dont have one, and neither does the website, sooo i've just plotted it on an actual graph. :P

OpenStudy (amistre64):

correlation coeff is a bugger to calculate by hand and my ti83 gave up the ghost a while back

OpenStudy (amistre64):

you got excel?

OpenStudy (anonymous):

No. I only have word and powerpoint. :/

OpenStudy (amistre64):

ive got mine loading, openoffice is a msoffice clone

OpenStudy (anonymous):

Oh okay. Was it easy to download?

OpenStudy (anonymous):

Is it still loading @amistre64

OpenStudy (amistre64):

it was simple to download yes but im used to excel commands, i cant find the corresponding commands in this one tho. it has a scatter plot but i havent messed with it enough to know how to work it properly :)

OpenStudy (amistre64):

we can work it by hand ... line of best fit, but then ill ahve to recall the pearson stuff

OpenStudy (anonymous):

Oh. Ok. If you can, i would like to work it by hand!

OpenStudy (amistre64):

but i just found the help file :) correl(a;b)

OpenStudy (amistre64):

got it we would need to define the slope of each best fit line: x with respect to y, and y with respect to x

OpenStudy (anonymous):

Understood.

OpenStudy (amistre64):

\[b=\frac{n\sum xy-\sum x\sum y}{n\sum xx-\sum x\sum x}\] \[b'=\frac{n\sum xy-\sum x\sum y}{n\sum yy-\sum y\sum y}\] \[r^2=bb'\]

OpenStudy (anonymous):

Ok, then?

OpenStudy (amistre64):

well, r = sqrt(r^2)

OpenStudy (anonymous):

Hmm. ok.

OpenStudy (anonymous):

So, do I have to plug this formula for every problem?

OpenStudy (amistre64):

if you insist on doing it by hand, sure. otherwise use ... the .. scatter ... plot ... tool n=8 xx x y yy xy 460865 1909 1051 139529 253318

OpenStudy (amistre64):

r = sqrt((8(253318)-1909(1051))^2/((8(460865)-1909^2)(8(139529)-1051^2)))

OpenStudy (anonymous):

hmmm. so the correlation is ......?

OpenStudy (anonymous):

correlation coefficient*

OpenStudy (amistre64):

ive given you the process, and even filled in your values .. its up to you to simplify it

OpenStudy (anonymous):

ok.

OpenStudy (anonymous):

1.00?

OpenStudy (anonymous):

Is 1. correct? Thats what i seemed to get.

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

Oh. Okay. so 0.9 and the second answer is July. Thanks!

OpenStudy (amistre64):

yep

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