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Mathematics 19 Online
OpenStudy (howard-wolowitz):

Number 1

OpenStudy (howard-wolowitz):

@geerky42

geerky42 (geerky42):

Other one said it's A, but I would say D. I would try for D.

OpenStudy (howard-wolowitz):

how do you know the answers so quickly?

geerky42 (geerky42):

Seen this question before.

geerky42 (geerky42):

Actually it's B. \(\dfrac{10h^2}{h} = 10h\)

geerky42 (geerky42):

Oops A*

OpenStudy (howard-wolowitz):

which one this one or the first one

geerky42 (geerky42):

It's A.

OpenStudy (howard-wolowitz):

16 or 14

geerky42 (geerky42):

Oh. 14.

geerky42 (geerky42):

D. Switch y to x; \[x = \sqrt{8y+1}\\x^2 = 8y+1\\x^2-1 = 8y\\\boxed{y = \dfrac{x^2-1}{8}}\]

OpenStudy (howard-wolowitz):

ok so 11. D 14. A 16. D

geerky42 (geerky42):

Yep.

OpenStudy (howard-wolowitz):

AWESOME

geerky42 (geerky42):

You got them all correct?

OpenStudy (howard-wolowitz):

are you supruised

geerky42 (geerky42):

Not really, Just wanna check, especially for 16.

OpenStudy (howard-wolowitz):

how did you learn how to do all of this?

geerky42 (geerky42):

Mostly by practice lol.

geerky42 (geerky42):

If you put in effort to learn and keeping try, you will be good.

geerky42 (geerky42):

More of less why you get homework. it's practice.

geerky42 (geerky42):

Well, \((f\circ g)(x) = f(~g(x)~)\), right? So you have \((f\circ g)(-2) = f(~g(-2)~)\) From graph, we can see that \(g(-2)= 0, right?\) Now we have \(f(~g(-2)~)=f(0)=\boxed{-4}\) Does that make sense?

geerky42 (geerky42):

B is correct.

OpenStudy (howard-wolowitz):

cool i actually got it right

geerky42 (geerky42):

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