Question

compare the measures.

Answer 1

Whats different?

Answer 2

the angle. @Andrewthehelper

Answer 3

Try using cosine law for both triangles: c^2 = a^2 + b^2 - 2abCos(C)

Answer 4

for the 42 degree triangle SU is 7.2 and for the 43 degree VX is 7.12 ?

Answer 5

@DoritosHero

Answer 6

I got for the first one:
c^2 = 4^2 + 5^2 - 2*4*5*Cos(42)
SU = c = 3.35

Answer 7

so it would be the same equation but cos(43) rather than cos(42) right?

Answer 8

Yep!

Answer 9

okay. one sec let me do the math then.

Answer 10

4.3 is what i got but that doesnt seem right.

Answer 11

wait. 3.42?

Answer 12

\[(VX)^{2} = (VW)^{2} + (WX)^{2} - 2(VW)(WX)\cos (VX)\]
\[(VX)^{2} = (5)^{2} + (4)^{2} - 2*5*4*\cos(43)\]
\[(VX)^{2} = 11.75\]
VX = 3.427

Answer 13

Yes that's right

Answer 14

omg i actually did it. lol

Answer 15

Yes you did! Good job :)