find the relative maximum value of g(x)
g(x)= 2/x^2+3

Question

find the relative maximum value of g(x)
g(x)= 2/x^2+3

dan815 · Answer

find the derivative of g(x) which is g'(x) and set to 0
solve this equation
g'(x)=0

cutiecomittee123 · Answer

Im still confused. Like is that all just the maximum is equal to 0?

dan815 · Answer

clarification; is it...
$$g(x)=\frac{ 2}{x^2+3} ~or~ g(x)=\frac{2}{x^2}+3$$

dan815 · Answer

Okay well, in your case you might not even need the derivative, this question has a vertical asymptote, depending on which equation we are looking at

cutiecomittee123 · Answer

Okay well how do I find the derivative?

dan815 · Answer

okay but first can you tell me which one of thsoe equations is your question

cutiecomittee123 · Answer

Oh my question is the fist one; (2)/(x^2+3)

dan815 · Answer

okk that changes everything.. there is no vertical asymtote then, so u need to find derivative

dan815 · Answer

you have to do chain rule

dan815 · Answer

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