Question

find the relative maximum value of g(x)
g(x)= 2/x^2+3

Answer 1

find the derivative of g(x) which is g'(x) and set to 0
solve this equation
g'(x)=0

Answer 2

Im still confused. Like is that all just the maximum is equal to 0?

Answer 3

clarification; is it...
\[g(x)=\frac{ 2}{x^2+3} ~or~ g(x)=\frac{2}{x^2}+3\]

Answer 4

Okay well, in your case you might not even need the derivative, this question has a vertical asymptote, depending on which equation we are looking at

Answer 5

Okay well how do I find the derivative?

Answer 6

okay but first can you tell me which one of thsoe equations is your question

Answer 7

Oh my question is the fist one; (2)/(x^2+3)

Answer 8

okk that changes everything.. there is no vertical asymtote then, so u need to find derivative

Answer 9

you have to do chain rule