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Mathematics 13 Online
OpenStudy (anonymous):

Factor This: 3x^3y-6x^2y^2+3xy^3

OpenStudy (xapproachesinfinity):

Factor 3xy first as a start

OpenStudy (anonymous):

3 x (-2 x + x^2 y - y^3) @Purpleloverr

OpenStudy (xapproachesinfinity):

No straight answer, read open study code of conduct

OpenStudy (xapproachesinfinity):

In fact it's not even correct

OpenStudy (anonymous):

Im confused D:

OpenStudy (xapproachesinfinity):

What is the common factor between all of the terms

OpenStudy (anonymous):

so first factor 3xy?

OpenStudy (anonymous):

3xy

OpenStudy (xapproachesinfinity):

Yah because that's the common factor

OpenStudy (anonymous):

yes i got that

OpenStudy (xapproachesinfinity):

OK factor that what will happen

OpenStudy (anonymous):

I got 3xy(x^2-2xy+y^2)

OpenStudy (xapproachesinfinity):

Good

OpenStudy (anonymous):

i dont see any other common factor

OpenStudy (xapproachesinfinity):

Now yhave a quadratic of the form a^2-2ab+b^2

OpenStudy (anonymous):

so treat it as a plug in?

OpenStudy (anonymous):

I am confused

OpenStudy (xapproachesinfinity):

No that's just a reminder for that it is of the same type

OpenStudy (anonymous):

so do you use the quadratic formula?

OpenStudy (xapproachesinfinity):

How do you factor a^2-2ab+b^2 you should know this

OpenStudy (xapproachesinfinity):

No binomial factorization.

OpenStudy (xapproachesinfinity):

We know that a^2-2ab+b^2=(a-b)^2

OpenStudy (xapproachesinfinity):

You will do the same to that Instead of a and b you have x and y

OpenStudy (anonymous):

Ok i see, sorry i was sick for the past 2 weeks so i missed a lot...

OpenStudy (xapproachesinfinity):

it's ok ^_- i was on the phone so i couldn't explain further :)

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