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OpenStudy (anonymous):
How do you find the pOH of 1 x 10^-9M? I need to use the pOH to solve for pH, but am unsure of how to get pOH.
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OpenStudy (anonymous):
To find the pOH from [OH-], you can use \(pOH=-log[OH^-]\)
OpenStudy (anonymous):
yes use the formuls POH=-log [OH-] where OH - is the concentration. of OH
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