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Chemistry 7 Online
OpenStudy (anonymous):

How do you find the pOH of 1 x 10^-9M? I need to use the pOH to solve for pH, but am unsure of how to get pOH.

OpenStudy (anonymous):

To find the pOH from [OH-], you can use \(pOH=-log[OH^-]\)

OpenStudy (anonymous):

yes use the formuls POH=-log [OH-] where OH - is the concentration. of OH

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