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Mathematics 23 Online
OpenStudy (anonymous):

Help Please!!!!!!!! Will award medal!!!!!!!!!!!!

OpenStudy (anonymous):

Using complete sentences, answer the following questions: What is the average common ratio between the successive height values of ball 1? Ball 2? Ball 3? Experimental errors may cause common ratios to have some variances within the data for one ball. Use the average common ratio.

OpenStudy (anonymous):

He recorded the height of each bounce, beginning with the height from which the ball originally fell, in the chart below: Ball 1 Description Ball 2 Description Ball 3 Description Height 1 (starting point) 3 ft 3 ft 3 ft Height 2 2.4 1.9 0.9 Height 3 1.9 1.2 0.3 Height 4 1.5 0.8 0.1 Height 5 1.2 0.5 0.02

OpenStudy (anonymous):

I will email or text a picture of the chart to whoever can help! It wont let me upload on here!

OpenStudy (anonymous):

@Awolflover1 @AMYCARTER @Astrophysics @amberosales @appleduardo @Angry @bohotness @Blonde_Gangsta @bfajardo6 @Babynini @BGrg007 @Ballahgirl42 @CanadianSteve99 @ChasingMaggie @Cman456 @Camibayybee @conad @cookielate @Deldrickg @Drumpad @dustin.leo.k @dmckinstry @EclipsedStar @elizadaniel @esam2 @epicpanda @EGN @FibonacciChick666 @familyguymath @FlashBT3 @flawlessswag @FierceDeity @ganeshie8 @globule @HelpBlahBlahBlah @heavenfun13 @HaileyD @holten @hacker45 @helbows @izzy529 @inlovewith5ds @Inquus @imalwaysbored14 @jim_thompson5910 @jagr2713 @justuu @Jaynator495 @jeweaver6895 @joshup @KyanTheDoodle @kkbrookly @KevlinKitten @karrleeyyee @Katykaty7 @Legends @LeilaJudeh @lilshane @leahhhmorgannn @lolhelpmepls @loves-sexy-girl @MTALHAHASSAN2 @Mr_Perfection_xD @MilkNCookies @Mateaus @mattyboyy @Mrhoola @Nnesha @nickymail48 @optiquest @Op1219 @openstudier101x @perl @pooja195 @Preetha @poopsiedoodle @prettygirl876 @Pika_Pika @quickthing @qwertyboy56 @redbeardd @ro561man @razorghost @ROBLOX @sammixboo @sleepyjess @ShadowLegendX @sissyedgar @Samus_Aran @SamsungFanBoy @suckerofmath @TwiztTiez @Tootles143 @Tuta @Tishockjo @Taey @vera_ewing @VengefulWave @wilsonbrandy @yowasup @zepdrix @ZDoubleM @ZoMbAsH @Zaaaya

OpenStudy (anonymous):

@Nnesha do you want me to send you a picture of the chart?

OpenStudy (anonymous):

I dont know how to do this ima sorry i could search it up

OpenStudy (anonymous):

If you could search it up that would be amazing because I am very lost on how to do it.

OpenStudy (anonymous):

@Australopithecus @aryandecoolest @AMYCARTER @Astrophysics @amberosales @appleduardo @bohotness @BlossomCake @brookiecokoie77 @becca1 @beamarie @Bazer1hunndo @Callisto @chmvijay @chycora @CREEPYMLPMASTER @CallMeKiki @Chiko_1278 @DarkMoonZ @Donblue22 @damonte212 @deana99 @Deldrickg @DenishaH @estrella81799 @familyguymath @FlashBT3 @Fuzure @flashp @FredFredBurgerYes @fuzzybird @Gokuporter @girllover123 @Gprev @globule @horsegirl325 @HaileyD @heather_theginger @HackberryAbby18 @HWBUSTER00 @hbrigando @iGreen @IrishBoy123 @izzy529 @ItsRhiBish @ItsRhiBish @Inquus @imalwaysbored14 @johnweldon1993 @Joel_the_boss @just_one_last_goodbye @Jaynator495 @josedavid @js7474 @k_lynn @kiamousekia @KevlinKitten @Kidneedshelp @karrleeyyee @Katykaty7 @leonardo0430 @lilshane @leahhhmorgannn @logan420 @lordhelix8th @lexluth0r @micahm @MrNood @monkeys @Mr_Perfection_xD @maddiegirl @Megan30400 @NathanHill1089 @nickymail48 @nerdrage18 @ninobaby123456 @notajewel @notthebest123 @OhMadisonn @openstudier101x @Preetha @prettygirl876 @princesskole33 @philcua @pandaluvs @Pika_Pika @quickthing @rational @rishavraj @rocky1718 @redbeardd @rockinhood @razorghost @sammixboo @shifuyanli @SyedMohammed98 @Samus_Aran @SamsungFanBoy @shadeyghost @TheAsker2002 @taylor12344 @TwiztTiez @tylermcmullen23 @Tishockjo @theopenstudyowl @UnkleRhaukus @uri @username.. @vera_ewing @von.co @VicBrad5 @veronica5656 @willtoll @xo.minnie.xox @YOUNGSUPERMAN @yajna @yowasup @zepdrix @ZnappyDooZ @zarkam21 @ZDoubleM @ZoMbAsH @Zaaaya

OpenStudy (fuzzybird):

i'm sorry hun i tried this one I couldn't get it.

OpenStudy (shadeyghost):

LOL, SOMEBODY ACTUALLY TAGGED EVERY USER IN MATH

OpenStudy (shadeyghost):

please, never do this again though

OpenStudy (anonymous):

WHOA! No Mass Tagging.

OpenStudy (fuzzybird):

ikr please don't do that again. :)

OpenStudy (shadeyghost):

this is not allowed

OpenStudy (znappydooz):

Okee dude, no party tagging... like... dont... its annoying

OpenStudy (anonymous):

Please dont mass tag @redmypony

OpenStudy (znappydooz):

Aks specific people, not everyone

OpenStudy (anonymous):

I'm desperate its been on here since yesterday afternoon

OpenStudy (shadeyghost):

http://openstudy.com/code-of-conduct

OpenStudy (anonymous):

sorry didn't know

OpenStudy (anonymous):

i am not good at math sorry :P

OpenStudy (fuzzybird):

hold on. I found a few other Open Study q's that are the same thing. they might help let me check out their answers.

OpenStudy (anonymous):

Nevertheless, do not mass tag. It violates OpenStudy's Code-of-Conduct.

OpenStudy (anonymous):

I'm sorry, but I have no idea. The best thing to do is guess. (If you truly have no idea) But, if you work on it, there will be a correct answer.

OpenStudy (fuzzybird):

Look at this one. A kind person gives a very detailed explanation. http://openstudy.com/study#/updates/54edbee5e4b0dc552b646c2d @redmypony

OpenStudy (leahhhmorgannn):

I really have no idea how to do this because I suck at math so, in the future, please refrain from tagging me unless you need help in English.

OpenStudy (mrnood):

I think you need to show the chart properly you need to work out the ratio of height 1/ height 2 height 2/height 3 height 3/height 4 height 4/height 5 for each ball

OpenStudy (anonymous):

Thanks @fuzzybird I think it it will help

OpenStudy (fuzzybird):

np

OpenStudy (anonymous):

For the first one, you need to decide "what do I have to do to the 3 to get to the 2.4? Then what do I have to do to the 2.4 to get to the 1.9?" What I did to come up with answer was divide the 3 by 2.4. I came up with 1.25. So I decided to see if, when I divide each term by 1.25, will I get the next term in line? I did. 3/1.25 = 2.4. 2.4/1.25= 1.9. 1.9/1.25 = 1.5. So the common ratio for ball 1 is 1.25

OpenStudy (anonymous):

1.58 is ball 2's common ratio. I found that the same way. See, the common ratio is only a reflection of the change in the data. The change from one point to the next is to divide it by 1.58.

OpenStudy (anonymous):

The average common ratio would be to add the 2 ratios you found and divide them by 2. That's the average common ratio

OpenStudy (anonymous):

@redmypony

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