Question

I will fan and give a medal to someone who helps me with 5 math questions :)

Answer 1

let me see

Answer 2

rewrite the radical as a rational exponent
\[\sqrt[4]{7^{5}}\]

A. \[7\frac{ 5 }{ 4 }\]

B. \[7^{20}\]

C. 7

D. \[7\frac{ 4 }{ 5 }\]

Answer 3

A

Answer 4

2.) Explain how the Quotient Of Powers was used to simplify this expression
\[\frac{ 2^{5} }{ 8 } = 2^{2}\]

A. By finding the quotient of the bases to be, 1/4 and cancelling common factors

B. By finding the quotient of the bases to be, 1/4 and simplifying the expression

C. By simplifying 8 to \[2^{3}\] to make both power bases two, and subtracting the exponents

D. By simplifying 8 to \[2^{3}\] to make both power bases two, and adding the exponents

Answer 5

@gerryliyana ^

Answer 6

C. By simplifying 8 to 2^3 to make both power bases two, and subtracting the exponents

Answer 7

\[\frac{ 2^5 }{ 8 }=\frac{ 2^5 }{ 2^3 }=2^{5-3} = 2^2\]

Answer 8

3) Rewrite the rational exponent as a radical exponent
\[\left(\begin{matrix}3\frac{ 2 }{ 3 } \\ \end{matrix}\right) \frac{ 1 }{ 6 }\]

A. \[\sqrt[6]{3}\]

B. \[\sqrt[9]{3}\]

C. \[\sqrt[18]{3}\]

D. \[\sqrt[6]{3^{3}}\]

Answer 9

@gerryliyana ^

Answer 10

you mean \(3^{\frac{ 2 }{ 3 }}\) or \(3\frac{ 2 }{ 3 }\) ?

Answer 11

\[3\left(\begin{matrix}2 \\ 3\end{matrix}\right)\]

Answer 12

the first or the second ??

Answer 13

second

Answer 14

ok wait

Answer 15

did you get it?

Answer 16

@theopenstudyowl help ^^^^^^

Answer 17

i am back

Answer 18

sorry, i was busy eating :)

Answer 19

that's fine :)

Answer 20

i just want to get these questions answered so i can go take my shower and get ready to go with my sis and my mom

Answer 21

\[\left( 3^{\frac{ 2 }{ 3 }} \right)\frac{ 1 }{ 6 } = 3^{\frac{ 2 }{ 3 }}3^{-\frac{ 3 }{ 2 }}=3^{\frac{ 2 }{ 3 }-\frac{ 3 }{ 2 }}=3^{\frac{ 2 \times 2 -3 \times 3}{ 6 }}=3^{\frac{ 4 -9}{ 6 }}=3^{\frac{ -5 }{ 6 }}\]

Answer 22

sorry i was wrong

Answer 23

i am gonna go with b?

Answer 24

i don't know if it's a, b, c, or d

Answer 25

what do you mean you wrong?

Answer 26

my last work was wrong

Answer 27

how?

Answer 28

it is \((3^{\frac{ 2 }{ 3 }})\), not \(3\left( \frac{ 2 }{ 3 } \right) \)

Answer 29

oh. ok

Answer 30

you should transform \(6^{-1}\ to\ 3^{-x}\). You should find x

Answer 31

and that would give me b?

Answer 32

where did you get b?

Answer 33

you said to transform \[\frac{ 1 }{ 6}\] to \[\frac{ x }{ 3 }\] and i multiplied 3 x 1 and 3 x 6 which would give me.............18

Answer 34

i'm wrong aren't I?

Answer 35

Nooo.,

Answer 36

It is not what I mean

Answer 37

\[\frac{ 1 }{ 6 } = 3^x\]
what is "x" ?

Answer 38

6 or 9? i am really bad at this X(

Answer 39

hmm

Answer 40

is it wrong?

Answer 41

yes

Answer 42

aw man :(

Answer 43

i thought i got it right

Answer 44

hmm i think you wrong

Answer 45

its should be \[3^{\left( {\frac{ 2 }{ 3 }} \right)\frac{ 1 }{ 6 }}\]

Answer 46

So

Answer 47

\[3^{\left( \frac{ 2 }{ 3 } \right)\frac{ 1 }{ 6 }}=3^{\frac{ 2 }{ 18 }}=3^{\frac{ 1 }{ 9 }}\]

Answer 48

the answer is b

Answer 49

got it?

Answer 50

you made a typo man

Answer 51

you know what i mean?

Answer 52

the answer is B

Answer 53

next question, please

Answer 54

Rewrite the rational exponent as a radical by extending the properties of integer exponents
\[2\frac{ 3 }{ 4 } \over 2\frac{ 1 }{ 2 }\]

A. \[\sqrt[8]{2^{3}}\]

B. \[\sqrt{2\frac{ 3 }{ 4 }}\]

C. \[\sqrt[4]{2}\]

D. \[\sqrt{2}\]

Answer 55

\[\frac{ 2^{\frac{ 3 }{ 4 }} }{ 2^{\frac{ 1 }{ 2 }} }=2^{\frac{ 3 }{ 4 }-\frac{ 1 }{ 2 }}= 2 ^{\frac{ 1 \times 3 - 2 \times 1}{ 4 }} = 2^{\frac{ 3-2 }{ 4 }}=2^{\frac{ 1 }{ 4 }} =\sqrt[4]{2}\]

Answer 56

that's all

Answer 57

Now, you know what should you choose

Answer 58

C

Answer 59

you got the point man!

Answer 60

can you help me with one more question?

Answer 61

ok, but don't forget to fan me and take the time to write a testimonial about me, i will appreciate it!

Answer 62

A rectangle has a length of \[\sqrt[3]{81}\] and a width of \[3\frac{ 2 }{ 3 }\]. Find the area of the rectangle.
A. \[3\frac{ 2 }{ 3 }\] inches squared
B. \[3\frac{ 8 }{ 3 }\] inches squared
C. 9 inches squared
D. \[9\frac{ 2 }{ 3 }\] inches squared

Answer 63

Help? @gerryliyana

Answer 64

@TheSmartOne quick help? ^

Answer 65

\[\sqrt[3]{81}= 81^{\frac{ 1 }{ 3}}=\left( 3^4 \right)^{\frac{ 1 }{ 3 }}=3^{\frac{ 4 }{ 3 }}= (3^2)^{\frac{ 2 }{ 3 }}=9^{\frac{ 2 }{ 3 }}\]

Answer 66

Extra quick help from me., are you satisfied?

Answer 67

@rikkibracamonte1999 are you still here?