easy area prob....can't get it tho
Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a mathematician, she suggests building fences described by and . Farmer Jones thinks this would be much harder than just building an enclosure with straight sides, but he wants to please his wife. What is the area of the enclosed region?
this is my integral i used: \[\int\limits_{-1}^{1} (x^2 + 9 ) - (9x^2) dx\] I thought it was outer minus inner but not sure....
@freckles @zepdrix could either of you help me please :)
`described by and .` The paragraph didn't past correctly. Is your integral correct?
paste*
i was just fixing to say something about that part
sorry let me fix that!
she suggests building fences described by y=9x^2 and y=x^2+9. Farmer Jones thinks this would be much harder than just building an enclosure with straight sides, but he wants to please his wife. What is the area of the enclosed region?
you got this one freck? :) i gotta take care of something
how did you find your lower and upper bounds?
graphed it
are they not right?
no
you want to find the intersections of the two curves
to do that you need to find when y=9x^2 is the same as y=x^2+9
to do that you need to find when 9x^2=x^2+9
ok let me see
you will get something extremely close to -1 and 1
but not exactly -1 and 1
ok it is 1.0606
well if you want the exact form: \[x^2+9=9x^2 \\ 9=(9-1)x^2 \\ \frac{9}{(9-1)}=x^2 \\ \frac{9}{8}=x^2 \\ x=\pm \sqrt{\frac{9}{8}}\]
ok i got it! haha thank u so much. it came out to be 12.727
that is a really close answer and is right if you are allowed to approximate
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