When uranium-238 emits an alpha particle, what isotope is created? Show the nuclear equation for this reaction.
Do you know what an alpha particle is?
we have the subsequent nuclear decay: \[\Large {U^{238}} \to T{h^{234}} + {\alpha ^4},\quad 4.5 \times {10^9}years\]
i have no idea what an alpha particle is
an alpha particel is the nucleus of the deuterium, which contains 2 protons and 2 neutrons, so its mass number is 2+2=4, furthermore, since an alpha particle doesn't have electrons, it charge is +4 e, where e=1.6*10^(-19) Coulombs
particle*
Alpha particles are typically written as |dw:1430667560812:dw| And yes, 2 protons and 2 neutrons leave the nucleus of the atom undergoing alpha decay.
ok so i would add that to uranium
No, as @Michele_Laino showed, the alpha particle is one of the products.
And we can figure out with the other product is by the number of protons left.
you have to add the alpha particle to Thorium 234
Since the uranium is losing 2 protons (it started with 92), it has 90 left over.
Which is Th
so its thorium 90 or am i missing another step
And it lost 4 from it's mass number (protons + neutrons), which is why the mass number of Th is 234.
It is Thorium-234
Thank you!!
Thank you! :)
You're welcome. :-)
And, @Michele_Laino Please don't just give answers. That is against policy and does not help the student to learn most effectively.
I don't gave the direct answer, I also wrote the created isotope, as requested by the question
@JoannaBlackwelder
the unique way to know the requested isotope, is to look at the decays diagram, as I have done @JoannaBlackwelder
This entire site just gives out answers. Should be called "do my homework for me"
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