Help with a hyperbola question? Find an equation in standard form for the hyperbola with vertices at (0, +- 2) and foci at (0, +- 7).
@ganeshie8
I know that the equation will be \(\dfrac{y^2}{a^2} - \dfrac{x^2}{b^2} = 1\), but I'm not sure how to find a and b
Vertices = \((0,~\pm a\)) compare that with given vertices and find \(a\)
So a would be 7!
No, 2!
Yes \(a=2\), next use below and find \(c\) first Foci = \((0,\pm c)\)
c would be 7 :)
use the raltion \(a^2+b^2=c^2\) and find \(b\)
\(b^2\) would be 45
Yep! plug them in the standard form of equation of vertical hyperbola
\(\dfrac{y^2}4 - \dfrac{x^2}{45}=1\)! "D
* :D
looks good! you may double check with wolfram http://www.wolframalpha.com/input/?i=focus+y%5E2%2F4-x%5E2%2F45%3D1
That was actually a lot easier than I thought it would be :)
it was easy because you remembered the standard form and formulas for vertices and foci :)
:) I always overthink math
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