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OpenStudy (sleepyjess):
Help with a hyperbola question?
Find an equation in standard form for the hyperbola with vertices at (0, +- 2) and foci at (0, +- 7).
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OpenStudy (sleepyjess):
@ganeshie8
OpenStudy (sleepyjess):
I know that the equation will be \(\dfrac{y^2}{a^2} - \dfrac{x^2}{b^2} = 1\), but I'm not sure how to find a and b
ganeshie8 (ganeshie8):
Vertices = \((0,~\pm a\))
compare that with given vertices and find \(a\)
OpenStudy (sleepyjess):
So a would be 7!
OpenStudy (sleepyjess):
No, 2!
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ganeshie8 (ganeshie8):
Yes \(a=2\),
next use below and find \(c\) first
Foci = \((0,\pm c)\)
OpenStudy (sleepyjess):
c would be 7 :)
ganeshie8 (ganeshie8):
use the raltion \(a^2+b^2=c^2\) and find \(b\)
OpenStudy (sleepyjess):
\(b^2\) would be 45
ganeshie8 (ganeshie8):
Yep! plug them in the standard form of equation of vertical hyperbola
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OpenStudy (sleepyjess):
\(\dfrac{y^2}4 - \dfrac{x^2}{45}=1\)! "D
OpenStudy (sleepyjess):
* :D
OpenStudy (sleepyjess):
That was actually a lot easier than I thought it would be :)
ganeshie8 (ganeshie8):
it was easy because you remembered the standard form and formulas for vertices and foci :)
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OpenStudy (sleepyjess):
:) I always overthink math
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