Find all values a for which there exists an ordered pair (a, b) satisfying the following system of equations:
a + ab^2 = 40b, and a - ab^2 = -32b.

Question

Find all values a for which there exists an ordered pair (a, b) satisfying the following system of equations:
a + ab^2  = 40b,  and a - ab^2  = -32b.

kittiwitti1 · Answer

$$a+ab^{2}\text{ & }=40b\text{, }a-ab^{2}\text{ & }=-32b$$Is this what you're asking for?

loser66 · Answer

$a(1+b^2)=40b\a(1-b^2)=-32b\\dfrac{40b}{1+b^2}=\dfrac{-32b}{1-b^2}$
Now, solve for b and then plug back to solve for a. If you are correct, the answer will be (12,3) for (a,b)

ryamorgan284 · Answer

https://mathway.com/