Question

Find all values a for which there exists an ordered pair (a, b) satisfying the following system of equations:
a + ab^2 = 40b, and a - ab^2 = -32b.

Answer 1

\[a+ab^{2}\text{ & }=40b\text{, }a-ab^{2}\text{ & }=-32b\]Is this what you're asking for?

Answer 2

\(a(1+b^2)=40b\\a(1-b^2)=-32b\\\dfrac{40b}{1+b^2}=\dfrac{-32b}{1-b^2}\)
Now, solve for b and then plug back to solve for a. If you are correct, the answer will be (12,3) for (a,b)

Answer 3

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