Help, please.. ;_;
r= sqr(5)^2 + (-12)^2
r should equal sqr17 right?

Question

Help, please.. ;_;
r= sqr(5)^2 + (-12)^2
r should equal sqr17 right?

onepieceftw · Answer

$$r=\sqrt{(5)^2+(-12)^2}$$

freckles · Answer

$$r=\sqrt{5^2+(-12)^2} $$
well 5^2=5(5)=25
and (12)^2=12*12=144

you are to add 25 and 144
then find the square root of their sum

onepieceftw · Answer

Okay that makes sense. Thanks! The way my course made it look was really confusing.

freckles · Answer

so you know it isn't sqrt(17) right?

freckles · Answer

sqrt(169)=?

-----------------
hint 13*13=169

onepieceftw · Answer

Yeah I got now. I just thought the sqr sign canceled out the ^2

freckles · Answer

nope nope
remember order of operations
do the operations inside the grouping symbol before taking care of the things outside the grouping symbols :)
but yeah glad you got it now :)

onepieceftw · Answer

The question I was answering was: "For an angle Θ with the point (5, −12) on its terminating side, what is the value of cosine?" and the answer is 5/13

freckles · Answer

ah I knew this was related to triangles

freckles · Answer

more specifically right triangles :)

freckles · Answer

let me know if you need any further help

onepieceftw · Answer

Sure, thanks!

onepieceftw · Answer

When Θ =  5 pi over 6, what are the reference angle and the sign values for sine, cosine, and tangent?

onepieceftw · Answer

What about this one, @freckles?

freckles · Answer

the reference angle is a deg measurement between 0 and 90
or in your case 
the reference angle is a rad measurement between 0 and pi/2

this number can be found by finding the acute measurement between the angle given and the x-axis

5pi/6 is located:
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