What is the value of x? Round to the nearest tenth. http://static.k12.com/calms_media/media/1579000_1579500/1579365/1/7e7f355332a5bdeac1b57e95381ed388a6e3d7ea/MS_IMC-150126-130904.jpg
do you know how to use the pythagorean theorem?
\(a^2+b^2=c^2?\)
@Michele_Laino
put 12 for a and 24 for c
\(12^2 + b^2 = 24^2\) find what \(12^2\) and \(24^2\) equal
so I find b^2?
you find b^2 and then solve for b
first find \(12^2\) and \(24^2\)
Use the Pythagorean Theorem. \(\sf a^2 + b^2 = c^2\) Where 'a' and 'b' are the two legs, and 'c' is the hypotenuse.
In this case, we are given the hypotenuse and the leg. Plug them in: \(\sf a^2 + 12^2 = 24^2\) Simplify 12^2 and 24^2.
here we have to apply the theorem of Pitagora, so we can write this formula: \[\Large x = \sqrt {{{24}^2} - {{12}^2}} = \sqrt {576 - 144} = \sqrt {432} \]
\(\sf a^2 + 12^2 = 24^2\) Subtract 12^2 to both sides: \(\sf a^2 = 24^2 - 12^2\) Find the square root of both sides: \(\sf a = \sqrt{24^2 - 12^2}\) That's how @Michele_Laino arrived there..lol.
that moment I decide to help someone, yet people are nice enough to butt in
yikes. im confused, thanks for all helping me, but I cant follow so many ppl
now using a calculator, for example windows calculator, we have: \[\Large \sqrt {432} = 20.784\] so your answer is: \[\Large x = 20.8\]
Simplify 24^2 and 12^2 first, like I and @Mehek14 stated.
Mehek... The user paid to get help from a QH =P
@TheSmartOne Or anybody else willing to help.
@iGreen like Mehek and I stated**
thanks all you guys :)
.-.
Erm..isn't the point to guide people?
thanks! :) @pikapow
np
i wish i could medal all you guys tho
You can. :P
Someone wants to get a medal *cough*
Take the medal you've given away. Open up a new tab(s)(depending on how many medals you want to give) Then give a medal to different people.
@TheSmartOne No, I don't. Considering I have over 4,000, one more doesn't really affect anything. Plus, I have already gotten one. Just thought I'd tell the user a trick or two :P
k, but it looks like you got a medal, so np right?
Yes, even if I didn't there still wouldn't be a problem. Just telling you for future cases since you asked.
Join our real-time social learning platform and learn together with your friends!