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Mathematics 26 Online
OpenStudy (anonymous):

What is the value of x? Round to the nearest tenth. http://static.k12.com/calms_media/media/1579000_1579500/1579365/1/7e7f355332a5bdeac1b57e95381ed388a6e3d7ea/MS_IMC-150126-130904.jpg

Mehek (mehek14):

do you know how to use the pythagorean theorem?

Mehek (mehek14):

\(a^2+b^2=c^2?\)

TheSmartOne (thesmartone):

@Michele_Laino

Mehek (mehek14):

put 12 for a and 24 for c

Mehek (mehek14):

\(12^2 + b^2 = 24^2\) find what \(12^2\) and \(24^2\) equal

OpenStudy (anonymous):

so I find b^2?

TheSmartOne (thesmartone):

you find b^2 and then solve for b

Mehek (mehek14):

first find \(12^2\) and \(24^2\)

OpenStudy (igreen):

Use the Pythagorean Theorem. \(\sf a^2 + b^2 = c^2\) Where 'a' and 'b' are the two legs, and 'c' is the hypotenuse.

OpenStudy (igreen):

In this case, we are given the hypotenuse and the leg. Plug them in: \(\sf a^2 + 12^2 = 24^2\) Simplify 12^2 and 24^2.

OpenStudy (michele_laino):

here we have to apply the theorem of Pitagora, so we can write this formula: \[\Large x = \sqrt {{{24}^2} - {{12}^2}} = \sqrt {576 - 144} = \sqrt {432} \]

OpenStudy (igreen):

\(\sf a^2 + 12^2 = 24^2\) Subtract 12^2 to both sides: \(\sf a^2 = 24^2 - 12^2\) Find the square root of both sides: \(\sf a = \sqrt{24^2 - 12^2}\) That's how @Michele_Laino arrived there..lol.

Mehek (mehek14):

that moment I decide to help someone, yet people are nice enough to butt in

OpenStudy (anonymous):

yikes. im confused, thanks for all helping me, but I cant follow so many ppl

OpenStudy (michele_laino):

now using a calculator, for example windows calculator, we have: \[\Large \sqrt {432} = 20.784\] so your answer is: \[\Large x = 20.8\]

OpenStudy (igreen):

Simplify 24^2 and 12^2 first, like I and @Mehek14 stated.

TheSmartOne (thesmartone):

Mehek... The user paid to get help from a QH =P

OpenStudy (igreen):

@TheSmartOne Or anybody else willing to help.

TheSmartOne (thesmartone):

@iGreen like Mehek and I stated**

OpenStudy (anonymous):

thanks all you guys :)

OpenStudy (igreen):

.-.

OpenStudy (igreen):

Erm..isn't the point to guide people?

OpenStudy (michele_laino):

thanks! :) @pikapow

OpenStudy (anonymous):

np

OpenStudy (anonymous):

i wish i could medal all you guys tho

OpenStudy (igreen):

You can. :P

TheSmartOne (thesmartone):

Someone wants to get a medal *cough*

OpenStudy (igreen):

Take the medal you've given away. Open up a new tab(s)(depending on how many medals you want to give) Then give a medal to different people.

OpenStudy (igreen):

@TheSmartOne No, I don't. Considering I have over 4,000, one more doesn't really affect anything. Plus, I have already gotten one. Just thought I'd tell the user a trick or two :P

OpenStudy (anonymous):

k, but it looks like you got a medal, so np right?

OpenStudy (igreen):

Yes, even if I didn't there still wouldn't be a problem. Just telling you for future cases since you asked.

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