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EASY! MEDAL AND FAN! What is the kinetic energy of a 45 kg object moving at 13m/s
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\[K = \frac{ 1 }{ 2 }m v^{2}\]
What represents m?
You have m and v given, substitute.
M is mass. Mass is measured in kilograms.
So it would be K=1/245x13^2?
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Im very bad at this, Appreciate the help. :)
Yep.
Can you break it down real quick on how to do this? Im sorry, Trying to help my son...
You're on the right track. Put 13 for for v and 45 for m.
Yes, Then what? Do I square 13?
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Yes. Like this \[K= \frac{ 1 }{ 2 }(45)(13)^{2}\]
\[13^{2} = 169\]So we can just do \[K = \frac{ 1 }{ 2 }(45)(169)\]
169
Just multiply through.
45x169?
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Yes. times 1/2
7605 / 2?
Yes.
Then you get your answer. I have to go to work. :)
3802.5
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