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Mathematics 21 Online
OpenStudy (anonymous):

Please help!Will medal and fan! Question in comments

OpenStudy (anonymous):

OpenStudy (anonymous):

ok hold on

OpenStudy (megankeeping):

The answer is A

OpenStudy (anonymous):

yea its a megan is right

OpenStudy (megankeeping):

if you look at it as x-2=0 and y+1=0 you can find x and y

OpenStudy (megankeeping):

Because x-2 and y+1 are in the brackets

OpenStudy (anonymous):

So, I reverse the signs to get the coordinates?

OpenStudy (megankeeping):

Pretty much

OpenStudy (megankeeping):

the equation of a circle is \[(x-x1)^{2}+(y-y1)^{2}=r ^{2}\] where r is the length of the radius and the centre is (x1,y1)

OpenStudy (anonymous):

Thank you. Can you help me with a couple others?

OpenStudy (megankeeping):

Sure

OpenStudy (anonymous):

OpenStudy (anonymous):

@MeganKeeping are you there?

OpenStudy (megankeeping):

Sorry, I'm back now

OpenStudy (anonymous):

Okay awesome

OpenStudy (megankeeping):

The equation of an ellipse is: \[\frac{ x ^{2} }{ a ^{2} }+\frac{ y ^{2} }{ b ^{2}}=1\] If b is larger than a, the major axis is the y-axis If a is larger than b, the major axis is the x-axis

OpenStudy (anonymous):

So, it would be A and C?

OpenStudy (megankeeping):

Yes

OpenStudy (anonymous):

Awesome cx I might have a few more in a minute

OpenStudy (anonymous):

OpenStudy (megankeeping):

Look at the equation of the ellipse. a^2 is the larger denominator and b^2 is the smaller denominator. In this case, a^2 = 49 and b^2 = 25 You need to find the value c c^2 = a^2 - b^2 so c^2 = 24 c=root24 The foci are c either side of the centre on the major axis

OpenStudy (megankeeping):

If you work out the centre and what axis the major axis lies on, you can work out the foci

OpenStudy (anonymous):

The center is (2,-1) and the major axis is the x axis

OpenStudy (megankeeping):

yes

OpenStudy (anonymous):

So, i think it's D

OpenStudy (megankeeping):

almost!

OpenStudy (anonymous):

B?

OpenStudy (megankeeping):

So the centre is (2,-1) and the foci are a distance c either side of the centre along the x axis. This means that the y value won't change but you need to add and subtract c to the x value of the centre

OpenStudy (anonymous):

Ohhhhh so it's C

OpenStudy (megankeeping):

c is root24 which is also 2root6

OpenStudy (megankeeping):

yes it is :)

OpenStudy (anonymous):

Awesome cx

OpenStudy (anonymous):

The first one is B, I think, and I'm fairly sure the second one is D

OpenStudy (megankeeping):

The major and minor axes always go through the centre so work out the centre first

OpenStudy (anonymous):

The center is (2,-1) so the answer would be D

OpenStudy (megankeeping):

Yes, that's the first one right

OpenStudy (anonymous):

And the second one is A

OpenStudy (megankeeping):

Yes :)

OpenStudy (anonymous):

And the second one is A

OpenStudy (anonymous):

I think the answer for this one is A

OpenStudy (megankeeping):

That looks right :)

OpenStudy (anonymous):

The first one is B and the second one is C

OpenStudy (megankeeping):

I think the first one is A but it looks like you've got the second one right

OpenStudy (anonymous):

B and C?

OpenStudy (anonymous):

@MeganKeeping are you there?

OpenStudy (megankeeping):

C and B

OpenStudy (megankeeping):

the eccentricity is c/a

OpenStudy (megankeeping):

c^2 = a^2 - b^2 where a^2 is the larger denominator and b^2 is the smaller denominator

OpenStudy (anonymous):

And I'm not sure on this one

OpenStudy (megankeeping):

a^2 = 81 b^2 = 9 so c^2 = 81 - 9 =72 e = c/a so e= root72/9 = 6root2/9 = 2root2/3 so the answer is D

OpenStudy (anonymous):

And then this one is B, I'm pretty sure

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