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Mathematics 20 Online
OpenStudy (chycora):

Choose the graph that correctly represents the solution set of the following system of inequalities. http://diagnostic.achievementseries.com/cdn//1/_graphics_math_14010f/53c56631-9547-4f11-99c5-e0f05e815265.gif A. http://diagnostic.achievementseries.com/cdn//1/_graphics_math_14010c/04539507-c904-4a7a-92bd-7d2189262b46.gif B. http://diagnostic.achievementseries.com/cdn//1/_graphics_math_14010a/0b8b781f-c456-4bb8-899f-d1d63bd7e0ac.gif C. http://diagnostic.achievementseries.com/cdn//1/_graphics_math_14010d/e60ddeb9-9663-4c86-9541-5610b5699450.gif D. http://diagnostic.achievementseri

OpenStudy (jacksepticeye):

Instead of analyzing each choice, let's just graph the system and compare with the choices. y >= -3x + 1 On a graph, place a point on y = 1

OpenStudy (jacksepticeye):

The slope is -3, so go down 3 and 1 right from that point. That's your second point.

OpenStudy (jacksepticeye):

Try point (1, 1) and see if it works in the inequality. y => -3x + 1 Is 1 >= -3(1) + 1 true? 1 >= -2 is true, so area wit point (1, 1) is part of graph.

OpenStudy (jacksepticeye):

this is the graph of the first inequality. Now we graph the second inequality on the same graph.

OpenStudy (jacksepticeye):

y => 1/2 x + 3 We have a y intercept of 3. graph that.

OpenStudy (jacksepticeye):

Now we have a slope of 1/2. That means a rise of 1 and a run of 2. Let's do that to get a second point.

OpenStudy (jacksepticeye):

@chycora

OpenStudy (chycora):

i'm here

OpenStudy (jacksepticeye):

k u got it laddy?

OpenStudy (jacksepticeye):

or am i not makin' cents

OpenStudy (chycora):

u r so tell me if i'm correct is the answer a

OpenStudy (jacksepticeye):

yes thats right laddy! booper dupper! :)

OpenStudy (chycora):

yay thanx

OpenStudy (jacksepticeye):

no problem laddy! ;)

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