Question

What is the value of this expression when n approaches infinity?

Answer 1

\[4-\frac{ 4 }{ n }+\frac{ 5 }{ n }+\frac{ 15 }{ 3n^2 }\]

Answer 2

20
10
5
4
1

Answer 3

@Michele_Laino

Answer 4

hint:
when n is a very large number, then the quantity 1/n is a veri little number, close to zero. For example, if n=500,000
then:
1/n=1/500000= a very little number (almost zero).
So in general we can write:
\[\begin{gathered}
\frac{1}{n} \to 0 \hfill \\
\hfill \\
\frac{1}{{{n^2}}} \to 0 \hfill \\
\hfill \\
\frac{1}{{{n^3}}} \to 0 \hfill \\
\end{gathered} \]

Answer 5

ok I'm back

Answer 6

4?

Answer 7

so the answer is 4-5=1

Answer 8

why 4-5?

Answer 9

or 14-4=10

Answer 10

just plugging in the zeros

Answer 11

hint:
\[4 - \frac{4}{n} + \frac{5}{n} + \frac{{15}}{{3{n^2}}} \to 4 - 0 + 0 + 0 = ...?\]

Answer 12

4

Answer 13

that's right!

Answer 14

I am tripping

Answer 15

thanks

Answer 16

thanks