what is the value of X in the equation -2x + 8 = _ -16
Will give medals to those that help me.
What is the value of x 6(-3 - x ) -2x = 14 wil give madals
When you solved for 'x', what did you get?
when I got to X i got 8 for the first one but you cant get 0 for X because then the equation doesn't make sense
\(-2x + 8 = -16 \rightarrow -2x = (-16-8) \rightarrow -2x = -24 \rightarrow x = \frac{-24}{-2}\)
What confused you on the second one?
okay for the second one am i supposed to leave the 6 once i times it to -3? or would the equation turn into -18*6x-2x=14?
With this as the equation, you first want to distribute the 6 into the parenthesis,6(-3 - x ) -2x = 14 \(6(-3-x) \rightarrow (6*(-3) + 6*(-x))\)
okay after i do that would i combine the like terms so 6x and 2x
Yes, exactly.
So after distributing you would have \(-18 -6x-2x=14\)
so after combining them i would have -18-8x=14
Exactly, nicely done. :)
okay now im lost again so i took -18-8x=14 and i added 8 to 14 so X would be left alone but what would i do after that?
You cannot add the -8 and the -18 together since the -8 is multiplied by 'x'. So first you need to move the -18.
okay so i didnt add the 8x to the -18 i added it to the 14
so i did -18-8x=14 +8=+8 witch have me 22
When you move the -18 from the left to the right, you have to 'add 18' to both sides. \(-18-8x=14 \rightarrow (+18) -18-8x=14 (+18) \rightarrow -8x = 14+18\)
okay so now i have 8x=32
so would X=4?
Now since your -8 is multiplied by x, the only want to reverse multiplication is through division. That is the right equation though you dropped a sign. So now you must DIVIDE by a -8 on both sides. \(-8x=32 \rightarrow \frac{-8x}{-8}=\frac{32}{-8}\)
You dropped the sign, but yes, excellent work. :)
so its -4
Yes. Good job.
would you mined helping me with one more?
Sure, what's the problem?
X+5=-6x-16
With this one you want to first get all the terms with an 'x' on one side and all the whole numbers onto the other.
okay I dont how i would do that
When moving from RHS (right hand side) to LHS (left hand side) of an equal sign you want to try and do one of two things. Either you add/subtract to both sides to get 0 or you multiply/divide to both sides to get 1.
In this case you are only adding/subtracting to make your first move. So how would you get a -6x from the RHS to the LHS and a +5 from the LHS to the RHS?
so would i subtract -6x to get to the LHS and then to get 5 to the RHS would i add?
I am really lost on this one im not understanding it at all
Remember that you're trying to get a '0' when adding/subtracting. So -6x -6x = -12x, which won't work because it changes the equation.
\(X+5=-6x-16 \rightarrow (6x)+x+5=-6x-16=(6x)\) You see how we add 6x to each side of the equation? We "cancel" out the -6x on the right but we add it back in on the left.
That should read: \(X+5=-6x-16 \rightarrow (6x)+x+5=-6x-16+(6x)\)
okay so right now my equation should be 6x+5=16?
It should be \(6x+x+5=16\)
err, dropped a sign again. \(6x+x+5=-16\)
So now can you get the 5 from the LHS to the RHS?
so i would subtract 5 and move it to the right?
You would subtract 5 from BOTH sides, yes.
oh and would the -6x stay negative once it was moved from right to left?
The 6x would not be negative because you are having to add 6x to cancel out that -6x from the RHS.
okay and now would my equation be 6x+x=-16-5?
Yes, exactly.
okay what would my next step be?
Next you need to consolidate terms. Add the 6x and x, then add the -16 and -5.
Once that is done, you will have a number "multiplied" by x. The only way to reverse multiplication is through division....
okay so now i should have 6x=-21?
what would give me an answer of -3.5
Remember, when you have a variable by itself, like 'x', that it is really the same as having 1x. So you had 6x+1x, what does that equal?
7x
Yes, and then x = ?
so that would change my answer to -3
Precisely. Excellent work. :)
okay im sorry but i dont know how to do the ones with fractions could you help me with that one?
Fractions?
Join our real-time social learning platform and learn together with your friends!