What is the ΔG for the following reaction at 25°C? SO3(g) + H2O(l) → H2SO4(l) Given: SO3(g):ΔG= –368 kJper mole H2O(l):ΔG= –237 kJ per mole H2SO4(l):ΔG= –689.9 kJ per mole 84.9 kJ 558.9 kJ –84.9 kJ –558.9 kJ
Do you know what triangleG means?
It's supposed to represent change over time
the "triangle" is the uppercase greek letter delta, \(\Delta\). it means "change" but not with respect to time
So for the question, you'd use \(\sf \huge \Delta G_{reaction}=\Delta G _{products}-\Delta G_{reactants}\)
@aaronq okay, but which ones are the products and which are the reactants?
Is that the whole question?
@Ajohnson2199 yes, the bottom four are the possible answers.
Okay, so I'm pretty sure that what the chemical equation yields are the products
So, H2SO4 is the product
And the reacts are SO3 + H2O
You following me?
@Ajohnson2199 okay so how would I put that into an equation?
Well, just plug in the numbers.
@Ajohnson2199 the answer is 84.9?
Did you check your work?
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