Question

Hi :D Just some questions I need help with, Ill medal its the last section of my class !!!

Answer 1

The equation of a circle with center (a,b) and radius r is
(x−a)2+(y−b)2=r2.
You know the center. You also know one point on the circle. The radius is the distance from the center of the circle to any one point on the circle.

So find the distance between (−1,4) and (3,−2) to get the radius. Then use the radius and the center to get the equation.

Answer 2

@Lexi724 does this help??

Answer 3

Hint:
if I have this equation:
\[\Large {\left( {x - a} \right)^2} + {\left( {y - b} \right)^2} = {r^2}\]
then the center of the circle is:
\[\Large C = \left( { - \frac{a}{2}, - \frac{b}{2}} \right)\]
and the radius is
\[\Large r\]

Answer 4

sorta the difference is 7.2

Answer 5

so 7.2 would be the radius

Answer 6

sorry I have made an error:
the center of the circle is:
\[\Large C = \left( {a,b} \right)\]

Answer 7

I dont understand any of this ,-,

Answer 8

so @Lexi724 what is your a and B in the equation??

Answer 9

we have to consider the generic equation:
\[\Large {\left( {x - a} \right)^2} + {\left( {y - b} \right)^2} = {r^2}\]

Answer 10

okay

Answer 11

so -2 is A, and 1 is your B

Center = (A, B)

Answer 12

the center is :
\[\Large C = \left( {a,b} \right)\]
and the radius is:
\[\Large r\]

Answer 13

now, I can rewrite your equation, as follows:
\[\Large {\left( {x - 2} \right)^2} + {\left( {y - \left( { - 1} \right)} \right)^2} = {2^2}\]

Answer 14

oh

Answer 15

so, what are a, b, and r?

Answer 16

So would my answer be D? and -2,-1 and 4