find the exact value by using a half-angle identity. sin (22.5 degrees)
Express \(\cos(2\theta)\) in terms of \(\sin(\theta)\) and then substitute \(\theta=22.5^0\)
use mathway.com
sqrt (2- sqrt 2)?
\(\bf 22.5\cdot 2\implies 45\qquad thus\qquad \cfrac{45}{2}\iff 22.5 \\ \quad \\ sin\left(\cfrac{{\color{red}{ 45^o}}}{2}\right)=\pm \sqrt{\cfrac{1-cos({\color{red}{ 45^o}})}{2}}\)
not quite @chris215 - if you list the steps you took then I can help you spot where you may have made a mistake
using the half angle formula for sin : sin((1/2)x) = 0 +/- sprt (1-cos(x) /2)
then i substitted 45 for x
and got sin(22.5) = sqrt ((1 - sqrt(2)/2))
what did you use for the value of cos(45)?
sqrt of 2
that is not correct
\[\cos(45)=\frac{1}{\sqrt{2}}=\frac{\sqrt{2}}{2}\]
oh yeah thats what I got sorry but next I used the positive sqrt and simplified
if you use that value and simplify then you do not end up with what you put above - please list your steps so I can spot where your mistake may have been
you can use the draw button below if that makes it easier for you
ok ill try my best to write it out on here
e.g.: |dw:1430951515425:dw|
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