Question

rate of change?? I will give medal !

Answer 1

http://gyazo.com/b6882ee3e82b9bc37363f9124084f726

^^ question is in link

Answer 2

@johnweldon1993

Answer 3

Hello again :P

lol so this is an easy one...remember the slope formula for 2 points?

\[\large \frac{y_2 - y_1}{x_2 - x_1}\]

Well here...when you plug in those 2 x-values...you get 2 different 'y' values

So basically you re-write that equation as

\[\large \frac{f(b) - f(a)}{b - a}\]

Where:
b = 5
a = 2
f(b) = what 'y' equals when you plug in x = 5
and
f(a) = what 'y' equals when you plug in x = 2

Answer 4

f(5)-f(2)/5-2 ??

Answer 5

Mmhmm, so you need to find out what that equation equals when you plug in 5 *f(5)

Then find what it equals when you plug in 2 *f(2)

Answer 6

isnt it already plugged in where i wrote it above?

Answer 7

Nope, alright so remember you were given an initial equation in the problem

\[\large g(x) = 2x^2 - 7x\]

Thinking back I should have used 'g' in my equation...so here let me re-write that too

\[\large \frac{g(b) - g(a)}{b-a}\]

To solve for g(b) you plug 5 into your g(x) equation
and to solve for g(a) you plug in 2 to your g(x) equation

Answer 8

so its g(5)=2x^2-7(2) sorry im really lost lol

Answer 9

No that's okay

So

\[\large g(x) = 2x^2 - 7x\]

right?

so g(5) means take your g(x) equation...and replace every 'x' you see with a 5

so

\[\large g(5) = 2(5)^2 - 7(5)\]

and solve that

Answer 10

g(5)=15?

Answer 11

Correct

And what about g(2) ? Remember...replace every 'x' you see with 2 now

Answer 12

-6?

Answer 13

Right again...so now our equation goes from

\[\large \frac{g(b) - g(a)}{b - a}\]

to

\[\large \frac{15 - (-6)}{5 - 2}\]

simplifying that we get...?

Answer 14

7

Answer 15

Correct!

Answer 16

thankyooou!!!

Answer 17

No problem you got all this :D