A brick walkway forms the diagonal of a square playground. The walkway is 20 m long. To the nearest tenth of a meter, how long is one side of the playground?
@10115658
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OpenStudy (anonymous):
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OpenStudy (anonymous):
x is the same length for both sides
OpenStudy (anonymous):
what would the formula look like to find x?
OpenStudy (lizz123):
a+b=20 squared
OpenStudy (anonymous):
since a and b are the same length, you can just replace it with x to get \[2x ^{2}=20^{2}\]
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OpenStudy (anonymous):
Do you understand that?
OpenStudy (lizz123):
kind of.
OpenStudy (anonymous):
Do you understand where i got the 2 from?
OpenStudy (lizz123):
yeah
OpenStudy (anonymous):
ok, so now we have to solve for x
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OpenStudy (anonymous):
20^2 becomes 400
OpenStudy (lizz123):
yup
OpenStudy (anonymous):
divide both sides of the equation by 2
OpenStudy (lizz123):
2x squared =200
OpenStudy (anonymous):
the 2 on the left side of the equation should cancel
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OpenStudy (anonymous):
\[x ^{2}=200\]
OpenStudy (anonymous):
does 200 make sense?
OpenStudy (lizz123):
ohh yeah I just forgot to cancel but I know where 200 came from
OpenStudy (anonymous):
thats not the answer
OpenStudy (anonymous):
how do you solve for x\[x ^{2}=200\]
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