Question

How would you format sin^2x+cos^2x=1 to show for sinx?

Answer 1

I don't know how to format \[\sin^2x+\cos^2x=1\] to sin, I think it should be \[sinx=\sqrt{-\cos^2x+1}\]

Answer 2

But you can't take the square root of a negative number, which is what has me confused.

Answer 3

\(\bf sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)=1-cos^2(\theta)
\\ \quad \\
sin(\theta)=\pm\sqrt{1-cos^2(\theta)}\)

Answer 4

Any thoughts guys?

Answer 5

So I was partially right?

Answer 6

well.. you're correct.... I simply put the negative cosine at the end, is all

Answer 7

Okay thanks jdoe!

Answer 8

yw