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Mathematics 25 Online
OpenStudy (anonymous):

HELP PLEASE!!!!!! MEDALLLLLL!!! A certain forest covers an area of 3300km2 . Suppose that each year this area decreases by 7.25% . What will the area be after 14 years? round your answer to the nearest square kilometer.

OpenStudy (anonymous):

@Mateaus

OpenStudy (anonymous):

@confluxepic

OpenStudy (anonymous):

@sammixboo

OpenStudy (anonymous):

Do you know how to find how much it has decreased the first year?

OpenStudy (anonymous):

No

OpenStudy (anonymous):

ok so you have 3300 square kilometers and it says that it decreases 7.25% of the 3300 square kilometer each year. So first you have to find how much is 7.25% of 3300.

OpenStudy (anonymous):

Do you know how to find how much is 7.25% of 3300?

OpenStudy (anonymous):

no lol

OpenStudy (anonymous):

Well to find how much is 7.25% of 3300. First you have to convert the percentage to decimals.

OpenStudy (anonymous):

The way you do that is grab 7.25% and divide it by 100. You will get a decimal.

OpenStudy (anonymous):

so \[\frac{ 7.25 }{ 100 } = 0.0725\]

OpenStudy (anonymous):

once you have this, you can find out how much is 7.25% of 3300. Multiply 3300 to 0.0725 and you will find how much 7.25% is of 3300.

OpenStudy (anonymous):

0.0725

OpenStudy (anonymous):

239.25?

OpenStudy (anonymous):

Yes that is 7.25% of 3300. Now that you have this, we go back to the problem. Since it says that its decreasing 7.25% yearly. That means that 7.25% is decreasing from 3300 or in other words 3300 - 239.25

OpenStudy (anonymous):

3060.75

OpenStudy (anonymous):

Yes, that is the total amount left after it decreased 7.25% in a year.

OpenStudy (anonymous):

you saw that 3300 was squared right?

OpenStudy (anonymous):

The question is asking how space will be left after 14 years.

OpenStudy (anonymous):

It's kilometer square.

OpenStudy (anonymous):

ok so what do i do subtract 3060.75 from 3300?

OpenStudy (anonymous):

After a year, it decreased 7.25% so now you have 3060.75km^2

OpenStudy (anonymous):

it has to be rounded

OpenStudy (anonymous):

to the nearest square km

OpenStudy (anonymous):

There is another way to do it but I can't remember. Now what you do is grab 3060.75 and do the same process you did with 3300.

OpenStudy (anonymous):

what do you mean?

OpenStudy (anonymous):

3060.75 * 0.0725

OpenStudy (anonymous):

Since each year is decreasing 7.25%.

OpenStudy (anonymous):

then whatever you get out it, subtract it from 3060.75, thats how much km^2 you are left after 2 years.

OpenStudy (anonymous):

i got 221.904375

OpenStudy (anonymous):

subtract that from 3060.75

OpenStudy (anonymous):

2838.845625

OpenStudy (anonymous):

Thats how much is left after 2 years.

OpenStudy (anonymous):

what do i round it to, 2838.8?

OpenStudy (anonymous):

is that rounded to the nearest square km?

OpenStudy (anonymous):

You can continue decreasing it until you reach to 14 years or you could use a formula hehe

OpenStudy (anonymous):

i dont understand

OpenStudy (anonymous):

So first you started with 3300 and after it decreased 7.25% in a year. Now 3300 is 3060.75. Then another year passed and 7.25% decreased from 3060.76 so on the second year there is 2838.8km^2 left of forest.

OpenStudy (anonymous):

so how do i get the answer?

OpenStudy (anonymous):

Well so far you have done 2 years out of 14 years. And that would take a lot of time, right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

There is a formula you can use: \[A(t) = 3300 ( 1 - 0.0725)^t\] where the 1 is really 100% and 0.0725 = 7.25% but both where divided by 100 so that we can have all in decimal and be usable to solve the problem.

OpenStudy (anonymous):

\[A(t) = 3300(.9275)^{14}\] after subtracting 1-0.0725 we end up with .9275 or 92.75% and t(time) = 14 so it's raised to the power of 14

OpenStudy (anonymous):

This will basically tell you how much km^2 of forest will be left after 14 years.

OpenStudy (anonymous):

so what is it?

OpenStudy (anonymous):

Well first solve (.9275)^14

OpenStudy (anonymous):

.9275*14?

OpenStudy (anonymous):

no 0.9275 to the power of 14

OpenStudy (anonymous):

so i have to do that 14 times?

OpenStudy (anonymous):

Use a calculator otherwise this would be a long process lol

OpenStudy (anonymous):

yeah 0.9275 multiplied by itself 14 times.

OpenStudy (anonymous):

Example :\[2^3 = 2*2*2\]

OpenStudy (anonymous):

4.881158292?

OpenStudy (anonymous):

.3486541637

OpenStudy (anonymous):

thats the answer?

OpenStudy (anonymous):

A(t) = 3300 ( .3486541637) now multiply both and you will get the answer.

OpenStudy (anonymous):

1150.558738

OpenStudy (anonymous):

Yep that is the answer

OpenStudy (anonymous):

rounded?

OpenStudy (anonymous):

to the nearest km

OpenStudy (anonymous):

\[1150.56km^2\]

OpenStudy (anonymous):

says round to the nearest square km still

OpenStudy (anonymous):

so would it be 1151?

OpenStudy (anonymous):

Yes, that's right .

OpenStudy (anonymous):

The radioactive substance uranium-240 has a half-life of 14 hours. The amount At of a sample of uranium-240 remaining (in grams) after t hours is given by the following exponential function. =At430012t14 Find the initial amount in the sample and the amount remaining after 30 hours. Round your answers to the nearest gram as necessary.

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