Question

question in comments

Answer 1

\[y^2-4x^2+8x-20=0\] right?>

Answer 2

yeah

Answer 3

you want the length of the major axis?

Answer 4

yes please

Answer 5

i think it is 8
lets see if we can work it out

Answer 6

ok thank you so much!

Answer 7

no i messed that way up let me start again

Answer 8

\[y^2-4x^2+8x=20\]
\[y^2-4(x^2-2x)=20\]
\[y^2-4(x-1)^2=20+4\]

Answer 9

damn anohter mess up

Answer 10

hmm let's me give it a try lol

Answer 11

\[y^2-4(x-1)^2=20-4=16\]thats better

Answer 12

eh good :)

Answer 13

divide by \(16\) get \[\frac{y^2}{16}-\frac{(x-1)^2}{4}=1\]

Answer 14

thats is exactly what i got when i did it !

Answer 15

i just don't know how to solve for the major axis

Answer 16

lol that is what i would have got it if wasn't so slow

Answer 17

now we know center is \((1,0)\) right?

Answer 18

the the length of major axis then is 4

Answer 19

and the vertices are 4 units up and down

Answer 20

so length of major axis is 8 i believe, not 4

Answer 21

oh yeah 2times 4
mistake on my part

Answer 22

\[\frac{y^2}{4^2}-\frac{(x-1)^2}{2^2}=1\] vertices are at \((1,-4)\) and \((1,4)\)

Answer 23

THANK YOU SO SO SO MUCH! THIS REALLY HELPED!