Solve by using Completing the Square
9x^2 + 3x = 2
so far I divided both sides by 9 so x^2 + 1/3x = 2/9 Then divide 1/3 by 1/2 then square it so x^2 + 1/3x + 1/36 = 2/9 + 1/36 so x^2 + 1/3x + 1/3 = 1/4
The last part should have 1/36, not just 1/3, but 1/36
oh, yea, I am sorry, you are correct
so now (x + 1/3)^2 = 1/4 right?
yup
so now I solve for x so sqrt both sides? x + 1/3 = + or - 1/2 (When 1/2 is positive) x + 1/3 = 1/2 - 1/3 - 1/3 x = 1/6 (When 1/2 is negative) x + 1/3 = - 1/2 - 1/3 - 1/3 x = -5/6?
yup
I got that marked wrong too, I'll have to ask him about it..
Wait, let me check
It is wrong. I am so sorry for not pay attention at the first time I noticed you
\[x^2 +\dfrac{1}{3}x =\dfrac{2}{9}\]
and you add 1/36 both sides, hence the expression is \(x^2 +(1/3)x+(1/6)^2 \), not as what you did
Hence it is \((x+1/6)^2 = 1/4\)
ok? yes? no?
ohh, I understand. :/ Okay at least I know now
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