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Mathematics 24 Online
OpenStudy (lifeisadangerousgame):

Solve by using Completing the Square

OpenStudy (lifeisadangerousgame):

9x^2 + 3x = 2

OpenStudy (lifeisadangerousgame):

so far I divided both sides by 9 so x^2 + 1/3x = 2/9 Then divide 1/3 by 1/2 then square it so x^2 + 1/3x + 1/36 = 2/9 + 1/36 so x^2 + 1/3x + 1/3 = 1/4

OpenStudy (lifeisadangerousgame):

The last part should have 1/36, not just 1/3, but 1/36

OpenStudy (loser66):

oh, yea, I am sorry, you are correct

OpenStudy (lifeisadangerousgame):

so now (x + 1/3)^2 = 1/4 right?

OpenStudy (loser66):

yup

OpenStudy (lifeisadangerousgame):

so now I solve for x so sqrt both sides? x + 1/3 = + or - 1/2 (When 1/2 is positive) x + 1/3 = 1/2 - 1/3 - 1/3 x = 1/6 (When 1/2 is negative) x + 1/3 = - 1/2 - 1/3 - 1/3 x = -5/6?

OpenStudy (loser66):

yup

OpenStudy (lifeisadangerousgame):

I got that marked wrong too, I'll have to ask him about it..

OpenStudy (loser66):

Wait, let me check

OpenStudy (loser66):

It is wrong. I am so sorry for not pay attention at the first time I noticed you

OpenStudy (loser66):

\[x^2 +\dfrac{1}{3}x =\dfrac{2}{9}\]

OpenStudy (loser66):

and you add 1/36 both sides, hence the expression is \(x^2 +(1/3)x+(1/6)^2 \), not as what you did

OpenStudy (loser66):

Hence it is \((x+1/6)^2 = 1/4\)

OpenStudy (loser66):

ok? yes? no?

OpenStudy (lifeisadangerousgame):

ohh, I understand. :/ Okay at least I know now

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