Question

This doesn't make sense does it..?

Answer 1

yes it does make sense

Answer 2

Yup looks like it makes sense to me. :)

Answer 3

How ? you can't graph those functions and they aren't parabolas.

Answer 4

what value of x makes f(0)?

Answer 5

0?

Answer 6

x^2?

Answer 7

f(4x+3) = f(0) when x=??

Answer 8

it is an odd question, i agree to that

Answer 9

-3/4?

Answer 10

have you had anything similar to it in your work?

ill admit that my idea might not have merit.

Answer 11

Similar

Answer 12

hard to post anything with all the lag on my end ...

Answer 13

lets assume something, since we have parabolas

y = a(x-h)^2 + k, has a vertex when x=h

agreed?

Answer 14

let y = f(x)

f(x) = a(x-h)^2 + k

let u = x-h , therefore x = u+h

f(u+h) = a(u)^2 + k, the vertex is still when x=h, or u=0

Answer 15

if u = 4x+3, u=0 when x=-3/4

Answer 16

still dont like that ....

Answer 17

lets do it this way ..

y is a paabola, its vertex on k is immaterial left to right ... since k is a up and down value

y = u^2 represents the parabola whose vertex is at u=0

f(u) = u^2

f(4x+3) = (4x+3)^2 has a vertex at 4x+3 = 0

Answer 18

does this seem right to you? it makes sense to me, but i dont want to suggest its correct :) its just a thought