Question

Given the exponential equation 3x = 243, what is the logarithmic form of the equation in base 10?

x = log base 10 of 243, all over log base 10 of 3
x = log base 10 of 3, all over log base 10 of 243
x = log base 2 of 3, all over log base 2 of 243
x = log base 2 of 243 all over log base 2 of 3

Answer 1

well if you take the log of both sides you get

\[\log_{10}(3^x) = \log_{10}(243)\]

now using the log law for powers its

\[x \times \log_{10}(3) = \log_{10}(243)\]

noe solve for x

Answer 2

would it be x=log10(243)/log10(30

Answer 3

(3)

Answer 4

that's correct... so looking at the answer choices.. I'd say the 1st one

Answer 5

thank you so much!