Question

Calculate delta G.Assume all reactions are carried out at 25 degrees C.

1. C2H4(g)+H2O(l)--->C2H5OH(l) delta Hrxn=-35.4 kJ delta S=-128.3 J/K

I'm not sure if I am doing this right. I think I start out by looking at the delta G values on the data table right?

That would mean that it would be: -174.9-68.1+(-237.2)= -480.2 delta G?

Then with the equation: delta G= delta H- T delta S, I plug in the values of all 3 to solve for the temperature?

-480.2= -35.4 -T(-128.3)
3.74= 0.27-T
13.85= -T
T=13.85