Question

integration problem. posting below with equation so it looks better haha

Answer 1

if someone could help me walk through it that would be highly appreciated!

Answer 2

Looks like a pretty standard u-sub

Answer 3

(u^4)^1/4 just becomes u

Answer 4

derivative of x+2 is 1

Answer 5

then integrate 1/(u+1)

Answer 6

ok so integral of (u+1)^-1

Answer 7

which gives ln(u+1) then plug back in (x+2)^1/4

Answer 8

So i think it's choice A

Answer 9

wolfram says choice B is the answer though

Answer 10

Sorry I haven't done integration in a while

Answer 11

Yah your u sub had me a little worried soccer guy :)
\[\Large\rm u^4=x+2\]\[\Large\rm 4u^3 du=dx\]We get a mess of u stuff on the left, ya?

Answer 12

no problem! Same here lol

Answer 13

hmm

Answer 14

ohh I think i see now. Let me try that lol

Answer 15

\[\Large\rm \int\limits \frac{1}{\sqrt[4]{x+2}+1}(dx)=\int\limits \frac{1}{u+1}(4u^3 du)\]

Answer 16

ya you're right, i got that part wrong

Answer 17

Something like that maybe? :o

Answer 18

when i plug in u would it just be \[u=\sqrt[4]{x+2}\]

Answer 19

Yes, after you've finished integrating though :D
not before!

Answer 20

Looks like you'll end up with a bunch of powers of u,
so writing it like this might make more sense: \(\Large\rm u=(x+2)^{1/4}\)

Answer 21

Uh oh, confused? :U
I can smell the smoke coming from your brain...

Answer 22

ok im trying to do the integration

Answer 23

Hmmmm.
The degree of the top is larger than that of the bottom....
Hmmmmm :) did it click yet?

Answer 24

is it like 4[ln(u+1)+(u^4/4)] + c ?

Answer 25

Hmm no.
I'm not sure what you did there.
Were you trying `parts` or something?

Answer 26

You need to do Polynomial Long Division as your first step.

Answer 27

with 4u^3/u+1 ?

Answer 28

yes :)