Question

find differentation of Y = √x+ 1/4 〖sin〗^2 (2x)

Answer 1

\[y = \sqrt{x} +1/2 \sin^2(2x)?\] if so you will have to use the chain rule

Answer 2

chain rule ? separated the sqrt x and the other one you mean ?

Answer 3

I don't know your question isn't very clear

Answer 4

I think he or she meant it as:
\[y = \sqrt{x + \frac{1}{4} \cdot \sin^2(2x)}\]

Answer 5

Sorry, I mean firstly tell your exact question..

Answer 6

What is the part under square root?

Answer 7

quotient rule

Answer 8

use quotient rule

Answer 9

\[\sqrt{x} + \frac{ 1 }{ 4 } \sin ^{2} (2x)\]

Answer 10

No need for quotient rule, chain rule and power rule is all you need

Answer 11

what's the \[\frac{ dy }{ dx }\] for this question ?

Answer 12

This is implicit differentiation

Answer 13

So every time you take a derivative of y, you also have y' or dy/dx

Answer 14

oh so this is the question

Answer 15

That is great..

Answer 16

if i use chain rule , how to differentiate the \[\sin^{2}\] ?

Answer 17

Firstly tell what is differentiation for \(\sqrt{x}\) ??

Answer 18

think of it as such