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Please help with an inverse Laplace Transform!
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\[\frac{ 1 }{ (s-1)^{4} }\]
\[e^t \frac{t^3}{6}\]
thank you! How did you work it out please?
let p = s-1 so you are looking for \[\mathcal{L}^{-1} \left\{ \frac{1}{p^4} \right\}\] which is\[\int\limits\limits_{0}^{\infty} \frac {t^3}{6} \ e^{-pt} dt \] \[\int\limits_{0}^{\infty} \frac {t^3}{6} e^{-(s-1)t} dt \] \[\int\limits\limits_{0}^{\infty} e^{t} \ \frac {t ^{3}}{6} \ e^{-st} dt \]
Ah ok thank you!!
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